2. Polynomials
easy

उपयुक्त सर्वसमिकाओं को प्रयोग करके निम्नलिखित गुणनफल ज्ञात कीजिए

$(3 x+4)(3 x-5)$

Option A
Option B
Option C
Option D

Solution

$(3 x+4)(3 x-5)$ :

Using the identity $(x+a)(x+b)=x^{2}+(a+b) x+a b,$ we have

$(3 x+4)(3 x-5) =(3 x)^{2}+[4+(-5)] 3 x+[4 \times(-5)] $

$=9 x^{2}+[-1] 3 x+[-20]=9 x^{2}-3 x-20$

Standard 9
Mathematics

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